Question

George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," George explains. Using complete sentences, demonstrate to George how the equation is still solvable.

Answer 1

http://openstudy.com/study#/updates/52b32ce2e4b03e81ff95262c
that might helped you

Answer 2

@terenzreignz @quixoticideals @elohelowlet @rach_ell @grace111 @xTabbiitthhaa

Answer 3

@kawaiicat123 do you think you could help me out on this question

Answer 4

Sure.

Answer 5

Okay, here is a simple example

1
x−1


looking at the equation

the denominator will be zero when x = 1

and as stated in the question dividing by zero is undefined.

What you do is restrict the domain, or the x values that you can use.


I this example you say you can input all real x values, except x = 1

that means you can solve it or graph it but the restriction will cause a gap.

Hope it makes sense!