What would the second derivative of the attached graph look like?
would it be some kind of a parabola?
please explain! thanks:)
1st derivative is the line tangent to the function, the second derivative would be the line tangent to the line tangent to the function. not sure the what the term is ..
so would it be like this? |dw:1393023624632:dw|
Probably the second one.
ohh okay cool! so normally, the second derivative will be some sort of line?
It's an x^4 graph, 2nd derivative will be and x^2 form
well if you had something like f(x) = x^3 f'(x) = 3x^2 f''(x) = 6x
@agent0smith what does that mean? x^2 ? :/
oh, it's an x^4 graph, didn't know that lol. f(x) = x^4 f'(x) = 4x^3 f''(x) = 12x^2
Remember any form of y=x^4 has a derivative y'= 4x^3, which has derivative y''= 12x^2
ohh.. and x^2 is a line? :/
or a parabola then?
x^2 is not a line, i think you know what x^2 is, you said it earlier in the question :P I would draw the first derivative graph first. then draw the second derivative.
hhaa parabola? if so , how can i tell if it's concave up or down?
Well it's a positive x^4. Which would have a positive 4x^3 and a positive 12x^2
a concave up parabola?
Yeah, but i think it'd be easiest to draw the first derivative, then use THAT to draw the 2nd.
ahh okay, so it would look something like this? |dw:1393024187151:dw|
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