Question

Solve for x, given the equation √(x-5)+7=11

Answer 1

Subtract 7 from both sides,

√(x-5) + 7 = 11
-7 -7

√(x-5) = 4

Square both sides, reason why you're squaring both sides it because you want to get rid of the radical,

x-5 = 16
+5 +5

x = 21

Check, if it doesn't work its an extraneous solution meaning it doesn't work with the original equation.


√(21-5) + 7 = 11

√(16) + 7 = 11

4 + 7 = 11

11 = 11 therefore this solution works

Answer 2

Trapezoid JKLM is shown on the coordinate plane below.

Trapezoid JKLM on the coordinate plane with ordered pairs at J negative 7, negative 2, at K negative 4, negative 2, at L negative 2, negative 5, at M negative 9, negative 5.

If trapezoid JKLM is translated according to the rule (x, y) → (x + 8, y - 3), what are the coordinates of point L'?

(1, -5)

(-10, 6)

(-5, 3)

(6, -8)