Question

FAN AND MEDAL AND FAN TESTIMONIAL TO WHOEVER HELPS!!!!
Solve 64x = 16^(x−1)
Idk how to do this please show me how?!

Answer 1

@Abdulhameed
@jdoe0001
@hartnn

Answer 2

check your question.

Answer 3

r u sure about the question ?

Answer 4

how?! that's what it says....
\[64x = 16^{x - 1}\]

Answer 5

yeah.....

Answer 6

ok but what did u write in the previous comment bcoz it say mathh processing error

Answer 7

so 64x = 16^(x-1)
the whole x - 1 thing is an exponent

Answer 8

if it was 16 not 16x it would be very easy , the problem is the x in 16x

Answer 9

hmmm...

Answer 10

i think may be it's 16^x not 16x

Answer 11

i have this thing here

Answer 12

the answer choice i picked was random.... don't bother with it

Answer 13

oh it's 64^x=16^x-1

Answer 14

wait.... i didn't put that?!?!?!

Answer 15

oooopppsss nevermind, i didn't ... sorry

Answer 16

\[64^x=16^{x-1}\]
\[\left( 4^3 \right)^x=\left( 4^2 \right)^{x-1},4^{3x}=4^{2x-2}\]
3x=2x-2
x=?

Answer 17

64=4^3
16 =4^2
64^x=4^3x
16^x-1=4^2x-2
4^3x=4^2x-2
3x=2x-2
3x-2x=-2
x=-2

Answer 18

thanks to both of you! :D

Answer 19

u r very welcome (^_^)

Answer 20

:D

Answer 21

hey @HelpBlahBlahBlah .... if ur online... can u give @surjithayer a medal? i can only give one person a medal..... but both helped me a lot thx :D

Answer 22

yea sure

Answer 23

kk thanks! :D

Answer 24

anytime :)

Answer 25

:D

Answer 26

lol :P

Answer 27

hey @Abdulhameed you still there?

Answer 28

yep :)

Answer 29

i wanna ask... what if the number on the first side is a fraction?
like in...

Answer 30

Solve 1/36 = 6^(x−3)

Answer 31

u have to make the numbers that have the exponents equal
1/36=1/6^2=6^-2
6^-2=6^(x-3)
-2=x-3
-2+3=x
x=1

Answer 32

ohhhh... ok Thanks again :D

Answer 33

Anytime :)

Answer 34

@31356

Answer 35

Correct! :D