Question

Given that f(x) = 2x + 1 and g(x) =3x-1/2 the quantity of 3x minus 1, divided by 2 solve for g(f(3)).

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Answer 1

@d3v13

Answer 2

@jdoe0001

Answer 3

\(\bf {\color{red}{ f(x)}} = 2x + 1\qquad g(x)=3x-\cfrac{1}{2}
\\ \quad \\
g(\quad f(x)\quad )=3({\color{red}{ 2x + 1}})-\cfrac{1}{2}\qquad \qquad g(\quad f({\color{blue}{ 3}})\quad )=3({\color{red}{ 2({\color{blue}{ 3}}) + 1}})-\cfrac{1}{2}\)