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At what height above the earth's surface, the value of g is same as in a mine 80 km deep?
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@sarah786
at height variation of graivty is g '=g(1-[(2h)/R]) and in depth g '=g(1-[d/R]) so (1-[(2h)/R])=(1-[d/R]) where R= radius od earth and d=80km(given) you have to find 'h '. calculate and solve Or it will cme like this... g(1-2h/R) = g(1-d/R) => 1-2h/R = 1- d/R =>2h/R = d/R => 2h = d => 2h = 80 => h = 40 m rest things are given above..... Source: http://www.meritnation.com/
thankq @sarah786
you're welcome but I just google'd it and I found all that , Did ya ???
noo i just popsted it directly..! :P
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lol ok then :P
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