A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed inside the cylinder as shown, what is the volume of the air space surrounding the cone inside the cylinder? (Use 3.14 as an approximation of π.)
Do you know how to find the volume of the cylinder? How about the cone?
No im not good at geometry @whpalmer4
Well, do you have a textbook? Class notes? I'm sure you've been given the formulas, and aren't expected to derive them on your own!
I have these formulas
The first step in the problem is to make sure you have all the needed tools. Two of those tools are the equation for the volume of a cylinder and the equation for the volume of a cone.
Okay! So, what is the height of the cylinder, and what is its radius? We'll call those \(h\) and \(r\) respectively. Read the problem, and respond with something like h=5 cm r=2 cm (except use the correct values, please!)
h=16 r=5 h=12 r=4
Good, you anticipated my next request :-) Let's find the volume of that cylinder. As my capable assistant stated, h = 16 and r = 5. The formula is \[V = \pi r^2 h\]Plug in the numbers and tell me what you get, though you should keep it in "symbolic" form: \(37\pi\) instead of \(116.239\), for example.
so V=Pi 5^2 (16)=400Pi ?
Very good! Now can you do the same for the cone, using r=4 and h = 12. The formula there is \[V=\frac{1}{3}\pi r^2h\]
=64Pi=201.06
Okay, if the volume of the cylinder is \(400\pi\) and the volume of the cone is \(64\pi\), how much space is left for air?
1457.698991?
Better to keep it in symbolic form while we figure out if you have the right expression or not. Then we don't have to worry about whether a difference in answers is because you had the wrong expression, or just didn't operate the calculator successfully.
336Pi?
Yes. What do you get when you convert that to a numeric form?
1055.04
That what I get, too.
would this be B?
Well, let's figure it out: we know the height is S, and we know the diameter is S. That means the radius is S/2. The volume of the cylinder is \[V = \pi r^2h = \pi (\frac{S}{2})^2S = \]
so the volume could = v=PiS^2?
No... \[\V = \pi(\frac{S}{2})^2*S = \pi*(\frac{S*S}{2*2})*S = \]
v=1/4PiS^3?
There you go!
im thinking in terms of c.. a=2c/Pi
\[C = 2\pi r\]\[r = \frac{C}{2\pi}\]right? then plug that into the formula for the area of a circle: \[A = \pi r^2\]
ok so it would be c^2/4Pi?
if by that you mean \[A = \frac{C^2}{4\pi}\]then yes.
this is the last one i promise
i got 12 cm^3 is that correct?
What's the formula for the volume of a pyramid?
\[V = \frac{1}{3}A_{base}h\]where \(A_{base}\) is the area of the base. What's the area of the base of this pyramid?
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