simplify e^(-2x)/(3e^(-4x))
\[\frac{e^{-2x}}{3e^{-4x}}\]Correct?
can it be e^2x/3
it can be!
Or if you don't like fractions, \[e^{2x}3^{-1}\]but that's maybe a bit unusual...
ok cool i just checked my calculator it rights
Did you do it by flipping the fraction and then simplifying, or did you just subtract the exponents right away?
both lol
Ah, good job! I like someone who checks their work.
i was curious of the 3e with the log rules
then i just realized its just a constant
Yep, a very special constant, but a constant nonetheless. Have you learned about imaginary/complex numbers yet?
im in diff q
Okay, then hopefully yes :-) I imagine you've seen \[e^{\pi i} - 1 = 0\]
except that should be a plus sign, duh
this was just to see if the website was legit and i was kind of iffy on the subject....but the website really works
yea i have seen it
so the eq e^xi +1=0
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