Question

Integration:

Answer 1

I did this problem but my answer is way off from the given answer :/ not sure what i did wrong. i set my u=sin(a theta)

Answer 2

\( \int \sin^3(a \theta ) d\theta = \int \sin^2 (a\theta) \sin(a\theta) d\theta = \int [1-\cos^2 (a\theta)] \sin(a\theta) d\theta\)

Answer 3

sub, \(u = \cos (a \theta)\)
\(du = -a\sin(a\theta) d\theta \)

Answer 4

:O

Answer 5

i didn't split my integral :|

Answer 6

happens :) looks u just did the first step ,

substitution involves two parts :
1) substitute u = something
2) find the relation between differentials : "du" and "dx"

Answer 7

hope you can finish it off...

Answer 8

yes thank you so much!:)