to show f(x)=|x+2| is continuous at x=-2 which of the following method is correct 1) |x+2| = -(x+2) when when x =2 lim x- -2(-) -(x+2) = 0 lim x- -2(+) (x+2) = 0 or lim x- -2 (-) f(x) = lim h-0 f(-2-h) lim x- -2(+) f(x) = lim h-0 f(2+h)

Question

to show f(x)=|x+2| is continuous at x=-2 which of the following method is correct 
1)  |x+2|  = -(x+2) when when x < 2 and
                 = (x+2) when x>=2  
lim x-> -2(-)  -(x+2)  = 0  
lim x-> -2(+)  (x+2)  = 0 

or 
lim x-> -2 (-) f(x) = lim h->0  f(-2-h)
lim x->  -2(+) f(x) = lim h->0 f(2+h)

anonymous · Answer

by process of elimination, 1 is wrong because -(x+2) is only when x <-2 since i acn have x = 1, and it would be 3, not -3