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Geometry 21 Online
OpenStudy (anonymous):

Picture Below! Given: Isosceles Triangle ABC with AD = AB Prove: Triangle BDA ~ Triangle ABC

OpenStudy (anonymous):

|dw:1393311258992:dw|

OpenStudy (wolf1728):

I'm guessing the ~ means similar. Anyway I can't see how the 2 triangles can be similar.

OpenStudy (anonymous):

The thing with the proof it's not like by seeing is by knowing the facts. I'm trying to see if theres something that goes with this.

OpenStudy (wolf1728):

In order to be similar, the angles of each triangle must equal the angles of the other. I can't see how they equal each other.

OpenStudy (anonymous):

Soo what we know is that angle A and B are = and that AD ='s AB

OpenStudy (anonymous):

If a line divides two sides of a triangle proportionally, then it is parallel to the third side

OpenStudy (wolf1728):

Specifically angle DAB = angle B

OpenStudy (anonymous):

Well. DAB + CAD right?

OpenStudy (wolf1728):

Where is the line that divides two sides of the triangle. and by DAB + CAD do you mean DAB = CAD?

OpenStudy (anonymous):

|dw:1393312074782:dw|

OpenStudy (anonymous):

DAB alone cant = angle B

OpenStudy (wolf1728):

Is there any additional information about this problem?

OpenStudy (anonymous):

No, but In a step we may need to draw something

OpenStudy (wolf1728):

It says we are given isosceles triangle ABC and that AD = AB. That is not expressed properly.

OpenStudy (anonymous):

Don't look at the picture to what's given, I didn't draw it perfectly lol. AD = AB

OpenStudy (e.mccormick):

"If a line divides two sides of a triangle proportionally, then it is parallel to the third side" means: |dw:1393312450627:dw|

OpenStudy (anonymous):

|dw:1393312470195:dw|

OpenStudy (wolf1728):

So it is definite that angle CAD = angle DAB?

OpenStudy (anonymous):

No, but If AD and AB are equal, that creates another Isosceles ?

OpenStudy (anonymous):

|dw:1393312634430:dw| Thats the picture the book gives for "if a line divides two sides of a triangle proportionally, then it is parallel to the third

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