Question

i need help i will give a medal

Answer 1

PKU (Phenylketonuria) is an autosomal recessive disease, in which the synthesis of amino acid Tyrosine from Phenylalanine is blocked. As a result, an excess of Phenylalanine gets converted into phenylketones, which appear in the urine. In severe conditions it may also result in damage to the brain. The gene responsible for this is p, whereas the gene P is responsible for normal synthesis of Tyrosine.

In a small population of Brazilian natives, the frequency of gene p, responsible for this disease, is 0.3. What must be the frequency of people who are heterozygous for this disease?
( p + q = 1, p2 + 2pq + q2 = 1)

0.56
0.35
0.42

Answer 2

@handyandy3

Answer 3

I have no idea man sorry i dont remember how to do this.

Answer 4

@undeadknight26

Answer 5

@sarah786

Answer 6

p + q = 1 if p is .3 then
q = 1-.3 =.7
So 2pq = heterozygous = 2(.3 x .7) = .42 Answer

Answer 7

its Hardy.Weinberg theorem .
you can also check your answer
put values p= .3 , q = .7 , 2pq=.42 in this formula

p2 + 2pq + q2 = 1

Answer 8

.3*2 + 2*.42 + .7*2 = 1

Answer 9

.6 + .84 + 1.4 = 1

Answer 10

So your answer is .42 is proved correct when you putted in formula, answer is equal to 1 .