What is the maximum number of rectangular blocks measuring 3 inches by 2 inches by 1 inch that can be packed into a cube-shaped box whose interior measures 6 inches on an edge? (A) 24 (B) 28 (C) 30 (D) 36 (E) 40
The Answer is D... But how!?
Ok.. how would u approach this problem?
I have no clue... I was thinking multiplying the dimensions to find area of some sort...
im studying for my SAT, and I screwed.. SO many questions I dont know how to do..
if you have to calculate in general, how many small boxes can fit into a large box which quantity you should calculate?
the number of small boxes divided in the big one
just have to use logic.. try to feel the problem.. "number of small boxes divided by the big one" ?? :P try solving this i have small cubes of sides 2cm and i have ONE BIGGG cube of side 8cm. how many cubes can fit?..
4?
thats wrong.. i ll work you through this.. the big cube.. how much space is present in it?? what is the volume?
I don't know because you didn't tell me the other dimensions? Am I amusing they are all 8? So 8x8x8?
yea.. duh.. its a CUBE .. cube has all sides equal :P so you are right.. 8x8x8 = 512 cubic cm.. that much SPACE is alvailable and similarly now u can calculate how much space the smaller cube acquires once you know these volumes.. THEn u can divide.. cause as u fill the larger cube with smaller cubes, the space gets filled up
OHH I answer my question... Lmao Im so dumb.. Thanks!
glad to have helped ;-)
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