Can someone help me with this?
Move the given graph down three and for each x, make it go twice as high as it does not.
\(\large{ \textit{vertical shift downwards by 3 units}\\ \begin{array}{llll} &&\downarrow \\ y=&2f(x)&-3\\ &\uparrow \end{array}\\\textit{shrinks the graph by a factor of "2"}}\) as already pointed out by Mertsj
what would that look like?
see where the vertex is ? do you know those coordinates?
2,4
so the vertex for 2f(x) -3 will be at ( 2, 2 * 4) or twice as much
so the vertex will be 2,8?
yeap
hmmmm
I kinda forgot about the -3
so after that, drop it by 3 vertically thata's where the vertex will end up after both transformations
http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiItMmFicyh4LTIpKzQiLCJjb2xvciI6IiNFODEyMTIifSx7InR5cGUiOjAsImVxIjoiMigtMmFicyh4LTIpKzQpLTMiLCJjb2xvciI6IiMxRTE4RDkifSx7InR5cGUiOjEwMDAsIndpbmRvdyI6WyItOS4wOTk5OTk5OTk5OTk5OTgiLCIxMS4yMTI0OTk5OTk5OTk5OTkiLCItMy4xMzg3NDk5OTk5OTk5OTkiLCI5LjM2MTI0OTk5OTk5OTk5OCJdfV0- <----- see the shifts ? it shrunk from the original by a factor of 2 then shifted down vertically by 3 units
so?
yeap
notice, it shrunk from the original by a factor of 2 then shifted down vertically by 3 units
thank you
yw
Join our real-time social learning platform and learn together with your friends!