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Question about derivative of ln(x*sqrt(x^2-6) Would it be derivative of lnx + lnsqrt(x^2-6) which would be 1/x + (1/2) (1/sqrtx^2-6) (2x)
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i think so
\[\ln(x\sqrt{x^2-6})=\ln(x)+\frac{1}{2}\ln(x^2-6)\]
taking derivatives gives \[\frac{1}{x}+\frac{x}{x^2-6}\]
I'm getting confused with x/x^2-6
wouldn't it be 1/sqrtx^2-6
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