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Medal for help! Help with finding the area between the curves: x=1-y^2 and x=y^2-1
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|dw:1393378519839:dw| \[x=1-y^2,y^2=1-x,x=y^2-1,y^2=x+1\] 1-x=x+1 x+x=1-1 2x=0,x=0 \[y^2=1,y=\pm 1,so~ points~ of~ intersection ~are~(0,1)~and~(0,-1)\] also they cut x-axis at (-1,0) and (1,0) changing y to -y ,equations remain same. Hence they are symmetric about x-axis. \[required~area=2[ \int\limits_{-1}^{0}y~dx+\int\limits_{0}^{1}y~dx ]\] \[=2\left[ \int\limits_{-1}^{0} \sqrt{x+1}~dx+\int\limits_{0}^{1}\sqrt{1-x}~dx\right]\] solve it.
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