Question

cubic root of 9x^4 * cubic root of 7x^8

Answer 1

like this?
\[\sqrt[3]{9x^4 } * \sqrt[3]{7x^8}\]

Answer 2

show your attempt at solving the problem

Answer 3

\[\sqrt[3]{9x^4?}*\sqrt[3]{7x^8}\]
\[\sqrt[3]{63x ^{12}}\]
this as far as I could go, I have to simplify it

Answer 4

you can write roots as fractional exponents. for example:\[\huge \sqrt(x)=x^\frac{1}{2}\]

\[\huge \sqrt{4}(x)=x^\frac{1}{4}\]

Answer 5

\[\huge \sqrt[4]{x}=x^\frac{1}{4}\]
oopsies

Answer 6

ok, so can you help solve this promblem

Answer 7

Apply the idea above to this:\[\huge \sqrt[3]{63x^{12}}\]

Answer 8

so it would be \[63x ^{12}1/3\]

Answer 9

yeah. and what happens to exponents raised to other exponents?

Answer 10

i dont know, we haven't learnt that

Answer 11

They're multiplied.

\[\huge {x^{\frac{1}{5}}}^{25} = x^\frac{ 25 }{ 5 } = x^5\]

Answer 12

so my problem would be \[x^4\]

Answer 13

you forgot the 63 I think

Answer 14

yea i did so my answer would be 63x4?

Answer 15

I think so, yeah.

Answer 16

ok thank you