Can someone help me with a few Questions?
That's why we're here.
Well yeah i know but not many people actually help me :(
What is your first question?
What is the first five terms of the sequence given by the formula an=6n+1? A.) 7,13,19,25,31 B.) 1,7,13,19,25 C.) 6,12,18,24,30 D.) 13,19,25,31,37
is it \[a_n=6n+1\]?
yeah
if so, start with \(n=1\) and get the first term \[a_1=6\times 1+1=7\]
so then it would be A right?
the second term is \[a_2=6\times 2+1=13\] but you could stop after \(a_1\) since only one choice begins with 7
yeah, A very unusual, it is usually C
can you help me with a few others?
sure why not?
Use summation notation to write the series 2.2+6.6+11+.... for 5 terms
is it an arithmetic sequence? i.e. do you add one number to get to the next?
its an arithmetic sequence
if so, since \(6.6-2.4=4.4\) and also \(11-6.6=4.4\) the terms look like \[2.2+6.6+11+15.4+19.8\] you need to write this in sigma notation, you could use \[\sum_{n=1}^52.2+(n-1)4.4\]
oops i meant \(6.6-2.2=4.4\) but the answer is still right
thanks i have just a couple more if you still dont mind
no problem did you understand what i wrote?
Yeah i think so im not very good at Algebra The choices that i had were \[\sum_{n=1}^{5}(-4.4+6.6n)\] \[\sum_{n=1}^{5}(-2.2+4.4n)\] \[\sum_{n=0}^{4}(-2.2+8.8n)\] \[\sum_{n=0}^{5}(-8.8+2.2n)\]
oh no sorry, go with the second one
the one with a \(4.4n\) in it
After you explained it i chose that one cause it was the only one with 4.4 instead of the negative
yeah, there are many different ways to write the same sum, so it can get confusing
Yeah but heres the next question Does the infinite geometric series diverge or converge?Explain 2+6+18+54+... A.) It diverges; it does not have a sum B.) It converges; it does not have a sum C.) It diverges; it has a sum D.) It converges; it has a sum
the numbers are getting bigger, so it DIVERGES that is a synonym for NOT having a sum
go with A
these two answers B.) It converges; it does not have a sum C.) It diverges; it has a sum make no sense no matter what the question is
Oh ok thanks i have one last muliple choice question to do then 3 that need to be explained in steps
go ahead and ask
Heres the multiple choice one What is the 10th term of the sequence 625,125,25,....? A.) 1/3125 B.) 1/125 C.) 1/1250 D.) 1/15625
looks like you are dividing by \(5\) each time
tenth term is \[\frac{625}{5^9}\]
ok hold on a sec
can't use your calculator for this, you will get a decimal look here http://www.wolframalpha.com/input/?i=625%2F5^9
looks like it is \[\frac{1}{3125}\]
i couldnt see the 9 on the fraction you had above that lol sorry
i can write \[\huge \text{bigger}\] if you like
No its fine lol
k got another? i will turn in to a pumpkin soon
yeah The numbers of seats in the first 12 rows of high-school auditorium form an arithmetic sequence. The first row is 9 seats. The second row is 11 seats. a.) Write a recursive form to represent the sequence b.) Write an explicit formula to represent the sequence c.) How many seat are in the 12th row?
recursion looks like \(a_1=9\) and \(a_n=a_{n-1}+2\) since the first one is 9 and you are adding two each time
explicit formula you have lots of choices. easiest is probably \(a_n=9+2(n-1)\)
or you could say \(a_n=7+2n\) either way, it is the same
since \(a_n=7+2n\) the 12th row has \[a_{12}=7+2\times1 2\] seats
so there would be 31 seats right?
yes
Kk Robin bought a computer for $1,250. It will depreciate, or decrease in value, by 10% each year that she owns it. a) Is the sequence formed by the value at the beginning of each year arithmetic, geometric, or neither? Explain b) Write an explicit formula to represent the sequence. c) Find the value of the computer at the beginning of the 6th year.
it is geometric because to decrease a number by \(10\%\) you multiply it by \(100\%-10\%=90\%=.9\) so each year the present value is multiplied by the same number (that makes it geometric) which in this case is \(.9\)
since each year it gets multiplied by \(.9\) you can write your sequence as \[a_n=1250\times (.9)^{n-1}\]
oh, actually scratch that use \[a_n=1250\times (.9)^n\]
at the beginning of year 6, it will be worth \(1250\times (.9)^5\) i think
i got 738.1125 when i did it on the calculator
yeah me too it is money so you might want to say \(\$738.11\)
that it?
One left
lol great
lol ok here it is Dante is making a necklace with 18 rows of tiny beads in which the number of beads per row is given by the series 3+10+17+24+... a) Use summation notation to write the series. Explain what the numbers in the summation represent in this situation and how you found the expression used in the summation. b) Find the total number of beads in the necklace. Explain your method for finding the total number of beads.
ok this is an easier one each row has 7 more than the previous one, starting at 3
you can use \[\sum_{n=1}^{18}3+7(n-1)\] or \[\sum_{n=1}^{18}-4+7n\]
if you use \[\sum_{n=1}^{18}3+7(n-1)\] the number 3 represents the number of beads in the first row and \(7(n-1)\) means each successive row has 7 more beads
as for adding it up, there are lots of ways to do it one is to use \(S=\frac{n(a_1+a_n)}{2}\) which in your case would be
\[\sum_{n=1}^{18}3+7(n-1)\]\[=\frac{18(3+122)}{2}\]
would that be 115 for the answer?
the 18 because there are 18 terms the 3 because it is the first number the 122 because it is the 18th number as \(3+7\times 17=122\)
oh no it is much bigger than that
oops
\[\frac{18(3+122)}{2}=9\times 125\]
that is all right?
so instead it would be 1125? thats what i got on calculator
that is what i get too
Ok Thank you so much for your help :)
yw and now stop doing math and take a break
Lol ok i will
Also you should get more medals than what you got but i cant give anymore..your awesome
Join our real-time social learning platform and learn together with your friends!