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Simplify, show steps please: (cosx/1+sinx)+(1+sinx/cosx)
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Get common denominators
\[\frac{\cos x+1+\sin x}{ 1+\sin x\cos x } ?\]
Not exactly..
Im just stuck on this whole equation.
Multiply everything through with a (1+sinx) and cosx
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So.. \[\LARGE \frac{cosx}{(1+sinx)}*\frac{cosx}{cosx}+\frac{1+sinx}{cosx}*\frac{1+sinx}{1+sinx}\] \[\LARGE = \frac{cos^2x}{(cosx)(1+sinx)}+\frac{(1+sinx)^2}{(cosx)(1+sinx)}\] Can you finish it?
I got \[\frac{ 1 }{ \cos x+\cos x \sin x }\]
Did you distribute that (1+sinx)^2?
ok i had my dad do it and his answer was. cscx
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