I tried to solve this question but I feel like my answer came out to be too large... Determine the formula mass of Pb(NO3)2 in g/mol and convert 0.250g Pb(N)3)2 to moles Pb(NO3)2.

I did the first part of the question and got an answer of 331g/mol.

Then for the second part I ended up with 1324 moles. I'm new to chemistry but to me that seems like a high number of moles? I set it up as: 0.250g/1mol=331g/mol/Xmol
0.250gX=331g/mol
0.250gX/0.250gX 331g/mol/0.250gX
X=1324 moles

Question

I tried to solve this question but I feel like my answer came out to be too large... Determine the formula mass of Pb(NO3)2 in g/mol and convert 0.250g Pb(N)3)2 to moles Pb(NO3)2.

I did the first part of the question and got an answer of 331g/mol.

 Then for the second part I ended up with 1324 moles. I'm new to chemistry but to me that seems like a high number of moles? I set it up as: 0.250g/1mol=331g/mol/Xmol 
0.250gX=331g/mol 
0.250gX/0.250gX     331g/mol/0.250gX 
X=1324 moles

anonymous · Answer

You have the first part right but not the second part....$$.250 g * \frac{ 1mol }{ 331g }$$
that way, grams cancel and you are left with moles. your answer should be 0.000755 moles or $$7.55*10^{-4} moles$$