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Chemistry 13 Online
OpenStudy (anonymous):

explain the structure of diborane?

OpenStudy (abb0t):

Well, it has tetrahedral geometry. I am not sure if you're fmiliar with point group, but it's D\(\sf_{2h}\)

OpenStudy (aayushi.somani):

If we consider the molecule B2H6 (diborane Figure 1), there are 12 valence electrons at our disposal for chemical bonding (B has 3, and H has 1, so 2xB + 6xH =12). Each terminal B–H bond is a standard vanilla two electron bond, and there are four of these, thus accounting for a total of eight electrons. This leaves a total of four electrons to share between the two bridging H atoms and the two B atoms. Consequently, two B–H–B bridging bonds are formed, each of which consists of two electrons (Figure 2), forming what are called threecenter- two-electron bonds (i.e., 3 atoms share 2 electrons) – sometimes called ‘banana’ bonds, as they are not linear but curved. Each B atom is, approximately, sp3 hybridized

OpenStudy (abb0t):

Uh, that photo doesn't look like diborane.

OpenStudy (aayushi.somani):

it is diborane i guess...!!

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