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express in terms of i the sum of radical -25 + 2 (radical -36) I got 11i + 2 am I right???
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\[-25+2\sqrt{-36}=-25+2(6)\sqrt{-1}=-25+12i\]
no it's radical negative 25
so\[\sqrt{-25}+2\sqrt{-36}\]?
yes
\[\sqrt{-25}+2\sqrt{-36}=5\sqrt{-1}+2(6)\sqrt{-1}=5i+12i=17i\]
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\[\sqrt{36}\] is 12i????
\[\sqrt{-36}=\sqrt{-1*(6^2)}=6\sqrt{-1}=6i\] However, the equation that we worked had a coefficient of two so \[2\sqrt{-36}=12i\]
ohhh okay I see, Thanks!!!
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