What is the slope of the line that contains the points (2, 6) and (-1, -6)?
I'll get you started \[\Large m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\] \[\Large m = \frac{-6-6}{-1-2}\] \[\Large m = ???\]
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 2}}\quad ,&{\color{blue}{ 6}})\quad &({\color{red}{ -1}}\quad ,&{\color{blue}{ -6}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)
hold do you type color in Latex!!? D:
\[\frac{ -12 }{ -3}\]
reduce that to get ???
what is 12/3 equal to?
4!
the two negatives cancel, so the result is positive therefore, the slope is 4
Thank you so much!
you're welcome
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