Question

Use the discriminant to determine how many x-intercepts the graph of the equation has:
y= -4x^2+3x-2
A.)None
B.)One
C.)Two
D.)Three

Answer 1

b^2-4ac =?

Answer 2

I'm pretty sure that's the formula

Answer 3

\(ax^2+bx+c\)
then
\(b^2-4ac = 0 \implies \text{one solution}\)
\(b^2-4ac > 0 \implies \text{two solutions}\)
\(b^2-4ac < 0 \implies \text{there are no real solutions}\)
you need to figure out what
\(b^2-4ac=\)

Answer 4

\(a = -4\\
b = 3\\
c = -2\)

Answer 5

what is \(3^2-4(-4)(-2)= \ ?\)

Answer 6

ok good luck

Answer 7

I don't get all this math crap. That's why I came here for answers.

Answer 8

take it slow, and ask question if you dont understand, we prefer more questions than less/none.

Answer 9

I just need to know how many intercepts the equation has. I have tried to figure it out and I can't. Math is my weakest subject.

Answer 10

\(3^2-4(-4)(-2)= \ ?\)

Answer 11

the answer to that will give the answer you seek...

Answer 12

answer it and ill show you why....

Answer 13

If you encounter answers that are the square root of negative numbers, the equation WON'T intercept the x axis and will have NO real solutions.

Answer 14

32

Answer 15

@zzr0ck3r 32?

Answer 16

3^2 -4(-4)(-2)= 9-32 < 0 so we have no real solutions because the discriminant is negative

Answer 17

if it were positive we would have 2,

if it were 0 we would have 1

3 will never be the answer...

Answer 18

Abbi - can you calculate this?
b² - 4*a*c =
3² - (-4*-2)

Answer 19

Thanks!