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Mathematics 13 Online
OpenStudy (nightmarenight):

Help??? will give medal and fan for right answers!! pls answer both!! attached below!!

OpenStudy (nightmarenight):

OpenStudy (bibby):

y = kx where k is a constant number is the formula for a direct linear variation IIRC

OpenStudy (bibby):

So for number 1, can you pick out which one is/isn't the direct linear variation?

OpenStudy (bibby):

for example. y = 3x y = 2x y = 6x etc. are all direct linear variations. y=x^2 y=x-1 aren't

OpenStudy (nightmarenight):

y=x-1? I dont think that was one of the answers

OpenStudy (bibby):

It isn't I'm trying to teach you what is and isn't a direct linear variation.

OpenStudy (bibby):

Do you want to start solving the first part?

OpenStudy (nightmarenight):

Sure

OpenStudy (bibby):

Which one do you think is or isn't a direct linear variation?

OpenStudy (nightmarenight):

I think b isnt

OpenStudy (bibby):

B is the only one that matches this format y = [some number] * x.

OpenStudy (bibby):

A/C/D are all formatted differently, using subtraction etc. You need a number multiplied by x. fractions are still numbers

OpenStudy (nightmarenight):

i was right???? o.O

OpenStudy (nightmarenight):

B is the answer

OpenStudy (bibby):

omg I can't read

OpenStudy (bibby):

good job o(〃^▽^〃)o

OpenStudy (nightmarenight):

thank you for your help ^o^

OpenStudy (bibby):

woah woah we're not even done

OpenStudy (bibby):

for the second part, 2 of the choices are DLV and 2 aren't.

OpenStudy (nightmarenight):

Oh? I forgot about the second one

OpenStudy (bibby):

So plug in y = 12 and x = 3 into A/B as they're the direct linear variations

OpenStudy (nightmarenight):

okay

OpenStudy (bibby):

Any progress?

OpenStudy (nightmarenight):

Is it A?

OpenStudy (bibby):

yup. 12 = 4*3. gj gj gj

OpenStudy (nightmarenight):

thank youuuu! ^o^ @bibby

OpenStudy (bibby):

np np ♥(✿◠‿◠) ♥

OpenStudy (nightmarenight):

Would you mind helping me with a few more? ^^ @bibby just two or three ^^

OpenStudy (bibby):

yeah, if I know the math. you can post it here or in another question

OpenStudy (nightmarenight):

@bibby thank you!

OpenStudy (bibby):

again, we want the equation to look like y = k (some number) * x^2

OpenStudy (nightmarenight):

mhm! ^^

OpenStudy (bibby):

I'm not sure how to demonstrate the working out of this, but D is the quadratic variation. y = 3x^2. I kinda just did it in my head

OpenStudy (nightmarenight):

D is the answer o:

OpenStudy (bibby):

D is the first answer, for the second you just plug in the numbers

OpenStudy (nightmarenight):

Is the second one c?

OpenStudy (bibby):

plug in the numbers, you get \[48=\frac{ 1 }{ 24 }*2^2 = \frac{ 4 }{ 24 }\]not exactly.

OpenStudy (nightmarenight):

Wait? D?

OpenStudy (bibby):

we're looking for some number that fits this description: 48 = ? * 2^2 48 = ? * 4

OpenStudy (bibby):

sssssssso cloossssse

OpenStudy (nightmarenight):

I dunno :c B?

OpenStudy (bibby):

You shouldn't be guessing lol. B is the only one that makes sense. B: y = 12x^2 y=48 x^2= 2*2 = 4 48 .= 4*12 = true

OpenStudy (nightmarenight):

I was right though! ahah ^^ I only have two more, sorry to be taking all your time, but I really appreciate it!

OpenStudy (nightmarenight):

OpenStudy (bibby):

My time, lol. it's cool, don't worry

OpenStudy (bibby):

an inverse variation is formatted like \[y=\frac{ k }{ x }\]

OpenStudy (bibby):

for the first one, try to derive the formula. f(x) = 30 x = 2\[30 = \frac{ ? }{ 2 }\] what is k?

OpenStudy (nightmarenight):

60?w haa?

OpenStudy (bibby):

exactly. so for 1a, the inverse variation looks like:\[y=\frac{ 60 }{ x }\] does that apply to everything in 1a?

OpenStudy (nightmarenight):

Yeah- because 30= 60/2 ?????

OpenStudy (bibby):

you have to do it to all the x's on the table, but yeah, it works

OpenStudy (nightmarenight):

yea

OpenStudy (bibby):

for part 2, which one is the inverse variation?

OpenStudy (nightmarenight):

wait what? i dunno which one was part 1

OpenStudy (bibby):

A

OpenStudy (bibby):

60/2=30 60/3=20 60/4=15 60/5=12

OpenStudy (nightmarenight):

Oh! okay ^^

OpenStudy (nightmarenight):

and for part two

OpenStudy (bibby):

for part 2, look for the inverse variation. remember they're in this format: \[\huge y= \frac{ k }{ x }\]

OpenStudy (nightmarenight):

yep!

OpenStudy (bibby):

that's not an answer choice

OpenStudy (bibby):

your other choice is plugging in y and x till you get an equivalence

OpenStudy (nightmarenight):

yes, I figure

OpenStudy (bibby):

So any ideas?

OpenStudy (nightmarenight):

8= k/2

OpenStudy (bibby):

yep

OpenStudy (bibby):

high five brotha

OpenStudy (nightmarenight):

and k is 16? haha

OpenStudy (bibby):

woah woah

OpenStudy (nightmarenight):

??

OpenStudy (bibby):

whoops. the equation is y=16/x k=16

OpenStudy (nightmarenight):

Ah, mhm ^^

OpenStudy (nightmarenight):

I think it's B

OpenStudy (bibby):

yus

OpenStudy (nightmarenight):

yeaayyy :D

OpenStudy (bibby):

>:D

OpenStudy (nightmarenight):

I have one more ^^

OpenStudy (bibby):

is we done yet

OpenStudy (bibby):

lay it on me brotha

OpenStudy (nightmarenight):

OpenStudy (bibby):

if you don't remember graph transformations (like me) You can use the x/y intercepts as a guideline. What is the x and y intercept of that equation?

OpenStudy (nightmarenight):

Not sure?/?

OpenStudy (bibby):

y-intercept = set x = to 0 x-intercept = set y = to 0

OpenStudy (bibby):

all you really need is the x intercept I think

OpenStudy (nightmarenight):

yeah so solve for g right

OpenStudy (bibby):

mhm, 0 = x-3

OpenStudy (bibby):

x = 3, the x intercept is 3. Also notice how there's no negative so the graph is a straight v

OpenStudy (nightmarenight):

Oh! It's A! thank you!

OpenStudy (bibby):

np, np

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