find the real or imaginary solutions by factoring x^4-10x^2+9=0
\(\large x^4-10x^2+9=0\implies \begin{array}{cccllll} {\color{red}{ (x^2)}}^4&-10{\color{red}{ (x^2)}}&+9=0\\ &\uparrow &\uparrow \\ &-9-1&-9\cdot -1 \end{array}\)
woops darn.. more typos =)
\(\large x^4-10x^2+9=0\implies \begin{array}{cccllll} {\color{red}{ (x^2)}}^2&-10{\color{red}{ (x^2)}}&+9=0\\ &\uparrow &\uparrow \\ &-9-1&-9\cdot -1 \end{array}\)
they exactly the same
oh wait nvm
but i just dont get like what you would do from there because i wasnt there the day the notes were taken and i just need something down on my paper for tomorrow
there's an assumption you know how to factor a quadratic, thus
yes
then those factors should factor it out :)
then just solve for "x", is a quartic, thus you'd get 4 values for "x"
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