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Mathematics 17 Online
OpenStudy (anonymous):

Point A is located at (0, 4) and point C is located at (−3, 5). Find the x value for point B that is located one over four the distance from point A to point C. −0.25 −0.5 −0.75 −1

OpenStudy (anonymous):

|dw:1393463290377:dw|

OpenStudy (anonymous):

-0.75!?

OpenStudy (anonymous):

mind helping me in one more thing? please?

OpenStudy (anonymous):

-0.75 no,you can ask.

OpenStudy (anonymous):

So you'd help?

OpenStudy (anonymous):

yes,you can ask.

OpenStudy (anonymous):

Using the image below, find the x value for the point that divides the line segment AB into a ratio of 2:3. −1 −0.4 0 0.5

OpenStudy (anonymous):

OpenStudy (anonymous):

|dw:1393464186344:dw| \[x=\frac{ mx2+nx1 }{m+n}\] \[y=\frac{ my2+ny1 }{ m+n }\] you can use this formula to find x .

OpenStudy (anonymous):

Oket let me plug in the numbers and tell you what i get

OpenStudy (anonymous):

yes you can show me .

OpenStudy (anonymous):

I got -2/5 , 4 not sure if I did it right

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

Yayy! So whats the next step?

OpenStudy (anonymous):

you want x value only \[x=\frac{ 2*5+3\left( -4 \right) }{2+3 }=\frac{ 10-12 }{ 5 }=-\frac{ 2 }{ 5 }=-0.4\]

OpenStudy (anonymous):

thank you thank you thank youu!!! I really needed this, and you taught me some things!

OpenStudy (anonymous):

you are most welcome,i am happy that i helped you.

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