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Trigonometry
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This is a quadratic form problem, where an overarching variable is given to an entire term in order to simplify the factoring process. I'll type it out in the comments section, please help.
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\[\sqrt{x+6} - 6\sqrt[4]{x+6} +8 = 0\]
\[(x+6)^{1/2}-6(x+6)^{1/4}+8=0\] To make it easier to see how to deal with the problem, consider the substitution \(t=(x+6)^{1/4}\). Then you can write the above equation as \[\left((x+6)^{1/4}\right)^2-6(x+6)^{1/4}+8=0\\ t^2-6t+8=0\] This can be factored to get \(t=4\) and \(t=2\). However, these aren't your solutions because they're in terms of \(t\), and not \(x\), the given variable. \[t=2~~\Rightarrow~~(x+6)^{1/4}=2~~\Rightarrow~~x=2^4-6=10\] \[t=4~~\Rightarrow~~(x+6)^{1/4}=4~~\Rightarrow~~x=4^4-6=250\]
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