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Mathematics 12 Online
OpenStudy (anonymous):

I don't know how to start.. Use linear approximation i.e. the tangent line to approximate 4.9^2 as follows: Let f(x) = x^2. The equation to the tangent line to f(x) at x=5 can be written in the form y=mx+b. m= b= Using this we find our approximation of 4.9^2 is...

OpenStudy (anonymous):

find the tangent line that goes through (5,25), then plug 4.9 in for x

OpenStudy (anonymous):

is y=10x+25 the tangent line?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oh no

OpenStudy (anonymous):

but 4.9^2 is a big number.

OpenStudy (anonymous):

it's 10x - 25

OpenStudy (anonymous):

10(4.9) - 25 = 24 and 4.9^2 = 24.01, the two number are very closed to each other

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