Question

Find the derivative

arcsin(t^2)

Answer 1

If I am correct, the formula is u' / sqrt(1-u^2)

Answer 2

u=t^2

= 2t/sqrt(1-t^4)

I that correct?

Answer 3

y?

Answer 4

y?

Answer 5

yeah why?

Answer 6

Why do I need to solve this problem?

Answer 7

why that formula

Answer 8

I found it in my textbook

Derivatives of Inverse Trigonometric Functions:

d/dx[arcsinu] = u' / sqrt(1-u^2)

Answer 9

then why ask us?

Answer 10

I want to make sure I am getting the correct answer

Answer 11

you are

Answer 12

Thanks :)