Question

Help Please!!!!

Answer 1

I will fan and medal

Answer 2

wat do u need help with

Answer 3

PAYING PHONE BILLS

Answer 4

haha really?

Answer 5

A community group is building a playground on a rectangular lot of land. The lot measures 6x by 9x, and the group wants to cut out an area for a circular jungle gym with a radius of 4x. How much of the land will be left over after the jungle gym is built?

Answer 6

let me read it first and see if i can

Answer 7

okay sorry dont know

Answer 8

\[A.) 38\pi x^2\]
\[B.) 22x^2 (27-2\pi)\]
\[C.) 2x^2 (27-8\pi)\]
\[D.) 38x^2\]

Answer 9

\[Area \ of \ a \ rectangle = length \times width \]\[Area \ of \ a \ circle = \pi r^{2}\]

ok... since the measurements of the rectangle field is
6x by 4x ...
the total area of the rectangle = (6x) x (9x) = ?

since the radius of the circle is 4x
\[Area\ pf \ the \ circle = \pi \times (4x) \times (4x) = ?\]

Answer 10

\[54x^2\]
\[16x^2 \times \pi\]

Answer 11

yep :)
now ...
area of the remaining land = area of the rectangular land - area of the circular land

Answer 12

please help me i give medals

Answer 13

not trying to be rude but can someone block me from this conversation so it does not pop up on my screen anymore ppppppppppppppllllllllllleeeeeeeeeeeeeaaaasssssseeeee

Answer 14

-_- ur being rude

Answer 15

sorry really not trying to be

Answer 16

which means...
\[remaining \ part = 54x^{2} - 16 x^{2} \pi\]

Answer 17

So 54x2 - 16x2×π right

Answer 18

yep :)

Answer 19

but u have to factorize it...

Answer 20

38x^2π

Answer 21

Would my answer be A?

Answer 22

no... u cant subtract
54x2 - 16x2×π
u can see that
54x^2 has the power of x^2
while
16x^2π has the power of x^2 plus the value of π...
since the value of π is not given ...π is also something like a unknown term...

so... 54x2 and 16x2×π r not like terms .. so u can subtract them ... but u can factorize them :)

Answer 23

if u take 2 common from the both terms...
\[54x^{2} - 16 \pi x^{2} = 2x^{2}( 27 - 8 \pi )\]

got it :) ?

Answer 24

gir that sucks im not good at factoring

Answer 25

gir my computer just loaded its slow lol yah I get it

Answer 26

kk ... ;)

Answer 27

Thank you for all ur time an effort

Answer 28

u r welcome... :) lol .. im gonna try finding a new phrase instead of "u r welcome" ... XD

Answer 29

lol okay

Answer 30

:p