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solve the system y=2-x and y=4x+7
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\(\bf {\color{red}{ y}}=2-x\\ y=4x+7 \\ \quad \\ y=4x+7\implies y=4({\color{red}{ 2-x}})+7\) solve for "y" then substitute that value in either equation and solve for "x"
hmmm lemme redo that =)
\(\bf {\color{red}{ y}}=2-x\\ y=4x+7 \\ \quad \\ y=4x+7\implies ({\color{red}{ 2-x}})=4x+7\) solve for "x" rather, and then substitute that on either equation and solve for "y"
ok
so it will be (-1,3) or (1,3)
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what did you get for "x"?
4x^2 I thank I gat confused with math
hmmm tis just a linear equation -> \(\bf ({\color{red}{ 2-x}})=4x+7\implies 2-x=4x+7\)
thank you that helped a lot
yw
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