Question

Derivatives.. did I do this right?

Answer 1

So I have..
\[\LARGE f(x)=\sqrt[4]{4+4x+x^3}\]
\[\LARGE =(4+4x+x^3)^{1/4}\]
\[\LARGE f'(x)=\frac{1}{4}(4+4x+x^3)^{-3/4}*4+3x^2\]
So it would end up as..
\[\Huge f'(x)=\frac{4+3x^2}{4 ~\sqrt[4]{(4+4x+x^3)^3}}\]

Answer 2

is that how you're suppose to do it?

Answer 3

;p yes you are correct

Answer 4

Yea, we're on chain rule and our professor insists we use the u and f(u).. which takes a bit longer since I already know it ._.