Question

A solution is made by dissolving 21.5 grams of glucose (C6H12O6) in 255 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.

Answer 1

use the formula: \(\Delta T=i*m*K_{\theta}\)

where, \(\theta=b\) when finding BP, and \(\theta=f\) when finding freezing point
(By that i mean use the appropriate constant.)

More on this: http://openstudy.com/study#/updates/521ecb3ae4b0750826e0c362

Answer 2

Okay Thank you!

Answer 3

no problem !