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Factor 9x^2 - 16
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Any ideas?
I know your supposed to find the the square roots. So the spuare root of 9 would be 3, and the square root of 16 would be 4 right?
$$\Huge 9x^2-16=(3x)^2-4^2$$
\[9x^2- 16 = (3x)^2-(4)^2 = (3x+4) (3x-4) \] are the required factors
6x^2-16?
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nope
How would I solve (3x)^2-4^2?
Have you seen the formula for the difference of two squares?
a^2-b^2= (a+b)(a-b)
$$\Huge a^2-b^2=(a+b)(a-b)$$
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a = 3x and b = 4
3x^2 - 4^2= (3x + 4)(3x-4)?
So that's my answer or do I need to simplify it more?
9x^2 - 16 = (3x)^2 - 4^2
Oh, I see what to do now. Thank you @skullpatrol
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Thanks for learning some new math :)
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