Question

Please help I will given metal given the triangle a=27 b=46 a=71degrees find B

Answer 1

You can use the law of sines for this...

\[\large \frac{\sin 71}{27} = \frac{\sin(B)}{46}\]

And solve for B

Answer 2

Did you get 87.2?

Answer 3

Hang on...is it SIDE A = 27 and SIDE B = 46, ANGLE A = 71 and we need ANGLE B ?

Answer 4

Yes

Answer 5

Okay...then this triangle does not exist?

\[\large \frac{\sin71}{27} \times 46 = 1.61\]

\[\large \sin^{-1} 1.61 = \cancel{\text{Error}}\]