Which relation is a function? A {(1, 2); (2, 3); (3, 4); (4, 5)} B {(1, 2); (1, 3); (1, 4); (1, 5)} C {(1, 2); (2, 3); (3, 4); (2, 5)} D {(1, 2); (3, 2); (3, 3); (4, 2)}
you didn't answer my question
well, that's what you're supposed to do :)
i don't know how, that's the thing
the 1st number of each pair is the "x" the 2nd number of each pair is the "y" so by no x-repeats, I meant the 1st number of each pair cannot have any repeats for a function
i still don't get it
ok... lemme \(\bf A {(1, 2);\quad (2, 3);\quad (3, 4);\quad (4, 5)}\\ B {(1, 2);\quad (1, 3);\quad (1, 4);\quad (1, 5)}\\ C {(1, 2);\quad (2, 3);\quad (3, 4);\quad (2, 5)}\\ D {(1, 2);\quad (3, 2);\quad (3, 3);\quad (4, 2)}\) notice the 1st number of each pair which set or line doesn't have any repeated 1st number per line?
ummm, C?
let's take a peek at C \(\bf A {(1, 2);\quad (2, 3);\quad (3, 4);\quad (4, 5)}\\ B {(1, 2);\quad (1, 3);\quad (1, 4);\quad (1, 5)}\\ C {(1, 2);\quad ({\color{red}{ 2}}, 3);\quad (3, 4);\quad ({\color{red}{ 2}}, 5)}\\ D {(1, 2);\quad (3, 2);\quad (3, 3);\quad (4, 2)}\) hmm we have one repeated "x" or 1st number, so is not that one
Hmmm A?
\(\bf A {({\color{blue}{ 1}}, 2);\quad ({\color{blue}{ 2}}, 3);\quad ({\color{blue}{ 3}}, 4);\quad ({\color{blue}{ 4}}, 5)}\quad \checkmark\\ B {(1, 2);\quad (1, 3);\quad (1, 4);\quad (1, 5)}\\ C {(1, 2);\quad (2, 3);\quad (3, 4);\quad (2, 5)}\\ D {(1, 2);\quad (3, 2);\quad (3, 3);\quad (4, 2)}\)
so, A set is a function
Thank you !
yw
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