Question

{Please help}
How do you find the factors of (x-3)(x-8)?

Answer 1

(x-3)(x-8) is completely factored

The factors are simply the terms in the parenthesis

Answer 2

So x-3 is one factor

x-8 is the other

Answer 3

How do you find the x values. My algebra teacher showed me but I forgot it.

Answer 4

can you find the x value?

Answer 5

well if that whole thing was set to 0, then you can use the zero product property to solve for x

Answer 6

if (x-3)(x-8) = 0, then...

(x-3)(x-8) = 0

x-3 = 0 or x-8 = 0

now solve each equation for x

Answer 7

I solved it on my notebook here. The original equation was x^2+5-21

Answer 8

wait let me try

Answer 9

x^2 + 5x - 21 does NOT factor to (x-3)(x-8)

Answer 10

notice how (-3)*(-8) = 24 and NOT -21

Answer 11

I mean -24 not 21 sorry

Answer 12

ok, notice how (-3)*(-8) = 24 which is positive, but we want negative 24

Answer 13

ohh ok i get it now Thank you very much!

Answer 14

so what does x^2 + 5x - 24 factor to?

Answer 15

have a good day sir.

Answer 16

well i got (x-3)(x+8) and the out come i got was x=3 or x=-8

Answer 17

I believe that is how my teacher told me how to do it.