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Question 8 of Integration Calculus
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Anyone one would do.
Hello
Let's start with part a
The problem made a substitution of u=x^8+12, right?
@NotTim
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eh, i thinkso
Now, can you find du?
8x^7
Right.
7/8(x^8+12)
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Wait. Let me rephrase the question. Sorry.
Forget what I just asked.
You got to the point where du=8x^7 What number do you have to multiply by 8x^7 in order to get to 7x^7?
7/8?
Right!
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Now, the original problem was \[\int\limits_{}^{}7x^7 \sqrt{x^8+12}dx=\int\limits_{}^{}A \sqrt{u}du\]
We agreed that du=8x^7
ja
ya
i gotta go; i'll be back real soon.
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I have to go, too...
oh darn
???
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