Question

find the largest of 3 consecutive integers such that 3 times the sum of the first and the third integer is equal to 30 more than 4 times the 2nd integer............PLEASE HURRY FIRST RESPONSE GETS AN MEDAL !!!!!

Answer 1

1st integer = n
2nd = n+1
3rd=n+2
form its equation:
3[(n) + (n+2)] = 30 + 4(n+1)
solve now.

Answer 2

n = 14

Answer 3

now.. largest integer = n+ 2
= 14 + 2
= 16 ans

Answer 4

3(2n + 2) = 30 + 4n + 4
6n + 6 = 34 + 4n
6n - 4n = 34 - 6
2n = 28
n = 14

n + 2 = 14 + 2 = 16

you are correct rukshar...good job explaining :)

Answer 5

thanks..

Answer 6

just telling the truth :)