Question

Expand ((a/n)-1)^2?

Answer 1

so far I have\[(\frac{a}{n}-1)(\frac{a}{n}-1)\]\[(\frac{a^2}{n^2}-\frac{a}{n}-\frac{a}{n}+1)\]\[\frac{a^2}{n^2}-\frac{2a}{2n}+1\]

Answer 2

did you f.o.i.l.?

Answer 3

wait nevermind

Answer 4

wrong type of question i was leaning towards a previosu lesson i had...sorry!!!

Answer 5

That's foil there, isn't it?

Answer 6

oh yes, sorry i read your math with a plus and a minus sign instead of only minus

Answer 7

\[(\frac{a^2}{n^2}-\frac{a}{n}-\frac{a}{n}+1)=(\frac{a^2}{n^2}-\frac{a+a}{n}+1)=(\frac{a^2}{n^2}-\frac{2a}{n}+1)\]

Answer 8

Brain fart, highfive!

Answer 9

that makes sense...so the two a/n's wouldnt turn out to be 2a/2n?

Answer 10

\[\left(\frac{a}{n}\right)^2-2\left(\frac{a}{n}\right)+1\]

Answer 11

Sorry my computer died on me but that is the complete answer

Answer 12

@doc.brown Now the equation has the form of a quadratic equation