Question

Integral of (3x-2)/(x+1)?

Answer 1

split the fraction ...

Answer 2

or a u sub maybe ...

let u = x+1, x = u-1
dx = du

\[\int \frac{3(u-1)-2}{u}~du\]
\[\int \frac{3u-5}{u}~du\]

Answer 3

^.^
\[\Large \frac{3x - 2}{x+1}=\frac{3x+3}{x+1}- \frac5{x+1}=3 - \frac5{x+1}\]

;)

Answer 4

yeah, that too ;)

Answer 5

Thank you so much everyone