Find the value of x and y.
one angle = 30, 2nd angle = 90 deg therefore third angle = 60 Hence given is a 30, 60 90 degree triangle
May i solve it using Trigonometry? @HourglassMage
I think I already found an answer, but I'm awful at proofs and my grade point average in geometry is starting to drop, so I want to be absolutely sure it's right
sure, whatever works for you
:)
Ok, wait...
\[\huge \sin 30^0 = \frac{x}{20} \] \[\huge \rightarrow \frac{1}{2} = \frac{x}{20} \rightarrow x= 10\]
!!!! Confusion, confusion
Exterminate confusing math! Exterminate!
But I got 10 for x, too, so I guess that's good
They also say to leave all answers reduced radicals, just fyi
\[\huge \cos 30^0 = \frac{y}{20}\] \[\huge \frac{\sqrt 3}{2} = \frac{y}{20}\] \[\huge 2y = 20 \times \sqrt3 \] \[\huge y = 10 \sqrt3 \]
I didn't do it with the first one, because it divided evenly, but I did leave y as a reduced radical
YES! Thnx, that's exactly what I got
Join our real-time social learning platform and learn together with your friends!