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Mathematics 18 Online
OpenStudy (anonymous):

Find the value of x and y.

OpenStudy (anonymous):

OpenStudy (anonymous):

one angle = 30, 2nd angle = 90 deg therefore third angle = 60 Hence given is a 30, 60 90 degree triangle

OpenStudy (anonymous):

May i solve it using Trigonometry? @HourglassMage

OpenStudy (anonymous):

I think I already found an answer, but I'm awful at proofs and my grade point average in geometry is starting to drop, so I want to be absolutely sure it's right

OpenStudy (anonymous):

sure, whatever works for you

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

Ok, wait...

OpenStudy (anonymous):

\[\huge \sin 30^0 = \frac{x}{20} \] \[\huge \rightarrow \frac{1}{2} = \frac{x}{20} \rightarrow x= 10\]

OpenStudy (anonymous):

!!!! Confusion, confusion

OpenStudy (anonymous):

Exterminate confusing math! Exterminate!

OpenStudy (anonymous):

But I got 10 for x, too, so I guess that's good

OpenStudy (anonymous):

They also say to leave all answers reduced radicals, just fyi

OpenStudy (anonymous):

\[\huge \cos 30^0 = \frac{y}{20}\] \[\huge \frac{\sqrt 3}{2} = \frac{y}{20}\] \[\huge 2y = 20 \times \sqrt3 \] \[\huge y = 10 \sqrt3 \]

OpenStudy (anonymous):

I didn't do it with the first one, because it divided evenly, but I did leave y as a reduced radical

OpenStudy (anonymous):

YES! Thnx, that's exactly what I got

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