Question

a

Answer 1

the output is a single Real value

Answer 2

for any (x,y) real pair, f(x,y) is a real number

Answer 3

\[\therefore ~f:R^2\to R\]

Answer 4

i want to say no ... but cant be certain off the top

Answer 5

R^2 is a set of ordered pairs, R can be modeled as the set of ordered pairs, (x,0) but that does not mean they are the same thing

Answer 6

i gotta be going for today, but good luck :)