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If k=x+3/x-3, and k^2-k=12, find x. (show work)
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Hint: the 2nd equation can be written in the form of a quadratic equation. Do so, please, and solve that equation for the 2 different values of k. Then subtitute those k values, one at a time, into the first equation.
so then the quadratic equation is: K^2-K-12=0 correct?
Yes. Now please solve that eq'n for k.
can you give me another hint, this is helping me a lot. what is the value of K
K^2-K-12=0 can be factored: (k-4)( ? ). Can you finish that?
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perfect, so then (K-4) and (K+3) because multipled -4 * 3 = -12 and added = -1 this is very helpful.
so then k1 = -3 and k2 = 4
but then do i substitute back into the equation?
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