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OpenStudy (anonymous):
Simplify and write the expression with positive exponents only.
b^-3/b^-5
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OpenStudy (anonymous):
use the rule
\[x ^{-a}=\frac{ 1 }{ x ^{a} }\]
OpenStudy (anonymous):
okay thanks :)
OpenStudy (anonymous):
anytime :)
OpenStudy (anonymous):
wait this is different because it has the variables and fractions.. idk how to set it up with the formula :( can you help me again?
OpenStudy (anonymous):
\[\frac{ b ^{-3} }{ b ^{-5} }=\frac{ b ^{5} }{ b ^{3} }\]
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OpenStudy (anonymous):
ohhhh okay thank you!
OpenStudy (anonymous):
do i just divide 5 and 2 after that?
OpenStudy (anonymous):
the rule for that
\[\frac{ x ^{a} }{ x ^{b} }=x ^{a-b}\]
OpenStudy (anonymous):
oh nvm then i had a diff one written down
OpenStudy (anonymous):
but what do i do with the exponents of 5 and 2?
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OpenStudy (anonymous):
\[b ^{5-3}=b ^{2}\]
OpenStudy (anonymous):
OHHH! i thought you put b^5-2. i was about to say 5-3=2
OpenStudy (anonymous):
okay i got it lol
OpenStudy (anonymous):
oh wait: my answer choices are different :(
a. b^-8
b. b^8
c. 1 /b^-8
d. 1/b^8
OpenStudy (anonymous):
ohhhh okay i see what they did, i forgot about the add and subtracting rule. i put in my caculator -3-5 so it equaled -8
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OpenStudy (anonymous):
so it must be b^-8? :)
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