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A student mixed two clear liquids together in a beaker and a solid precipitate formed. His data is shown in the table below. What is the mass of the beaker? 5 g 10 g 15 g 17 g 32 g (Picture attached below.)
Intriguing picture. :)
Hold on it's not attaching. -_-
Liquid reactant A/ 10 g Liquid reactant B/ 17 g Beaker+solid product/ 32 g ( this is the image typed out.)
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Oh, well if there isn't any loss from the reaction, it's just an arithmetic problem. :) So the mass of the beaker = Beaker + solid product - (A + B) = 5
So it would be A?
Yep
thank bye, P.S. you take forever to type.
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