Evaluate the following limit: lim (x ->3) x^2-16x+64/x^3-21x^2+144x-320
The function is continuous at \(x=3\). What do you get when you plug in 3?
i need help with factorising the denominator (the answer is -1/2 by the way)
You don't have to factorise it unless you want to know for sure that it doesn't have a singularity at \(x=3\)... Before you force yourself to do that, why not try to plug in \(x=3\) first?
If you happen to get 0 in the denominator, then you can focus your efforts into factorising it.
alright i got the answer, so I just substitute 3 into the whole question. Does that mean that for every question, we sub the limit in unless when it equals to zero then we factorise it?
That could be your general strategy, sure. What I meant to say is that before you even go about factorising, check to see if there is a discontinuity at the approaching value. If you do get a zero in the denominator, THEN try to factorise the numerator and denominator.
Okay, that is more clear now. Thank you for your help.
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