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Mathematics 16 Online
OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

OpenStudy (yttrium):

Can I help?

OpenStudy (anonymous):

line goes through the origin, so all you need is the slope since \((1,6)\) is on the graph, as well as \((0,0)\) the slope is \(6\)

OpenStudy (anonymous):

yes @Yttrium

OpenStudy (yttrium):

if you know the two point form equation of a line. \[y-y _{1} = \frac{ y _{2}-y _{?} }{ x _{2}-x _{1} }(x-x _{1})\] if you know that form, you can easily form the equation by just pluggin in the values for (x1,y1) and (x2,y2). x and y are as is.

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