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Mathematics 9 Online
OpenStudy (vshiroky):

verify

OpenStudy (vshiroky):

OpenStudy (vshiroky):

(6,-4)

OpenStudy (anonymous):

no try again

OpenStudy (vshiroky):

(6,-2)

OpenStudy (anonymous):

multiply the second equation by \(-2\) and then add

OpenStudy (anonymous):

at this point you can almost do it in your head i bet

OpenStudy (vshiroky):

I think it's cause I am rushing now to go to work lol

OpenStudy (anonymous):

go slow, i know you got this

OpenStudy (cwrw238):

3x + 4y = 10 x + 2y = -2 form 2nd equation x = -2-2y now plug this into first equation: 3(-2-2y) + 4y = 10 -6 -6y + 4y = 10 -2y = 16 can you continue?

OpenStudy (vshiroky):

So if it's the same line it's infinitie

OpenStudy (anonymous):

you're killing me

OpenStudy (jdoe0001):

\(\large \begin{array}{llll} 3x+4y=10&&\quad \cancel{3x}+4y=10\\ x+2y=-2&{\color{red}{ \times -3}}\implies &\cancel{-3x}-6y=6\\ \hline\\ &&\qquad \qquad \square =\square \end{array}\)

OpenStudy (vshiroky):

Lol I was asking for a different one with that @satellite73

OpenStudy (anonymous):

\[3x + 4y = 10\\ x + 2y = -2 \]\[3x+4y=10\\-2x-4y=4\]

OpenStudy (cwrw238):

oh - deosn't it ask for substitution method for this one?

OpenStudy (jdoe0001):

hmmm oh ... yeah =(

OpenStudy (cwrw238):

can u continue with i left off vshiroky?

OpenStudy (cwrw238):

*where

OpenStudy (cwrw238):

if -2y = 16 what is y?

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